TheEmployeetable holds all employees. Every employee has an Id, a salary, and there is also a column for the department Id.
+----+-------+--------+--------------+
| Id | Name | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1 | Joe | 70000 | 1 |
| 2 | Henry | 80000 | 2 |
| 3 | Sam | 60000 | 2 |
| 4 | Max | 90000 | 1 |
+----+-------+--------+--------------+
TheDepartmenttable holds all departments of the company.
+----+----------+
| Id | Name |
+----+----------+
| 1 | IT |
| 2 | Sales |
+----+----------+
Write a SQL query to find employees who have the highest salary in each of the departments. For the above tables, Max has the highest salary in the IT department and Henry has the highest salary in the Sales department.
+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT | Max | 90000 |
| Sales | Henry | 80000 |
+------------+----------+--------+
Solution 1
SELECT D.Name AS Department, E.Name AS Employee, E.Salary FROM Employee AS E, (SELECT DepartmentId,MAX(Salary)AS max FROM Employee GROUP BY DepartmentId) AS T, Department AS DWHERE E.DepartmentId = T.DepartmentId AND E.Salary = T.maxAND E.DepartmentId = D.id
Solution 2
SELECT Department.name AS Department, Employee.name AS Employee, SalaryFROM Employee JOIN Department ON Employee.DepartmentId = Department.IdWHERE (Employee.DepartmentId , Salary) IN ( SELECT DepartmentId,MAX(Salary) FROM Employee GROUP BY DepartmentId );
Solution 3
SELECT D.Name AS Department, E1.Name AS Employee, E1.Salary AS SalaryFROM Department AS D JOIN Employee AS E1 ON D.Id = E1.DepartmentIdWHERE E1.Salary = ( SELECT MAX(E2.Salary) FROM Employee AS E2 WHERE E2.DepartmentId = E1.DepartmentId );
Solution 4
SELECT Department.Name Department, e1.Name Employee, e1.SalaryFROM employee e1 LEFT JOIN employee e2 ON e1.DepartmentId = e2.DepartmentId AND e1.Salary < e2.Salary JOIN Department ON e1.DepartmentId = Department.IdWHERE e2.Salary is null