197_Rising Temperature
Given aWeather
table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.
+---------+------------+------------------+
| Id(INT) | Date(DATE) | Temperature(INT) |
+---------+------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------+------------------+
For example, return the following Ids for the above Weather table:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
Solution
Use DATEDIFF() function to only inner join yesterday's temperature.
SELECT w1.Id AS Id
FROM Weather AS w1 INNER JOIN Weather AS w2
ON DATEDIFF(w1.Date, w2.Date) = 1
WHERE w1.Temperature > w2.Temperature;
Last updated
Was this helpful?