27_Remove Element
Given an array nums
and a value val
, remove all instances of that value in-place and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given nums = [3,2,2,3], val = 3,
Your function should return length = 2, with the first two elements of nums being 2.
It doesn't matter what you leave beyond the returned length.
Solution:
def removeElement(nums, val):
"""
:type nums: List[int]
:type val: int
:rtype: int
"""
# corner cases
if len(nums) == 0:
return 0
write_index = 0
for i in range(len(nums)):
if nums[i] != val:
nums[write_index], nums[i] = nums[i], nums[write_index]
write_index += 1
return write_index
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