339_Nested List Weight Sum
339. Nested List Weight Sum
Level: easy
Tag: depth-first search
Question
Given a nested list of integers, return the sum of all integers in the list weighted by their depth.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1
Given the list [[1,1],2,[1,1]], return 10. (four 1's at depth 2, one 2 at depth 1)
Example 2
Given the list [1,[4,[6]]], return 27. (one 1 at depth 1, one 4 at depth 2, and one 6 at depth 3; 1 + 4*2 + 6*3 = 27)
Solution 1: BFS, recursive
flatten a list of lists
Time: O(n)
Space: O(1)
# """
# This is the interface that allows for creating nested lists.
# You should not implement it, or speculate about its implementation
# """
#class NestedInteger(object):
# def __init__(self, value=None):
# """
# If value is not specified, initializes an empty list.
# Otherwise initializes a single integer equal to value.
# """
#
# def isInteger(self):
# """
# @return True if this NestedInteger holds a single integer, rather than a nested list.
# :rtype bool
# """
#
# def add(self, elem):
# """
# Set this NestedInteger to hold a nested list and adds a nested integer elem to it.
# :rtype void
# """
#
# def setInteger(self, value):
# """
# Set this NestedInteger to hold a single integer equal to value.
# :rtype void
# """
#
# def getInteger(self):
# """
# @return the single integer that this NestedInteger holds, if it holds a single integer
# Return None if this NestedInteger holds a nested list
# :rtype int
# """
#
# def getList(self):
# """
# @return the nested list that this NestedInteger holds, if it holds a nested list
# Return None if this NestedInteger holds a single integer
# :rtype List[NestedInteger]
# """
class Solution(object):
def depthSum(self, nestedList):
"""
:type nestedList: List[NestedInteger]
:rtype: int
"""
return self.depthPartialSum(nestedList, 0)
def depthPartialSum(self, List, depth):
sum = 0
for i in List:
if i.isInteger():
sum += i.getInteger() * (depth + 1)
else:
sum += self.depthPartialSum(i.getList(), depth + 1)
return sum
Solution 2: BFS, iterative
Time: O(n)
Space: O(n)
class Solution(object):
def depthSum(self, nestedList):
"""
:type nestedList: List[NestedInteger]
:rtype: int
"""
depth, ans = 1, 0
while nestedList:
ans += depth * sum([x.getInteger() for x in nestedList if x.isInteger()])
nestedList = sum([x.getList() for x in nestedList if not x.isInteger()], [])
depth += 1
return ans
Solution 3: DFS, using stack
class Solution(object):
def depthSum(self, nestedList):
"""
:type nestedList: List[NestedInteger]
:rtype: int
"""
if len(nestedList) == 0:
return 0
stack = []
sum = 0
for n in nestedList:
stack.append((n, 1))
while stack:
next, d = stack.pop(0)
if next.isInteger():
sum += d * next.getInteger()
else:
for i in next.getList():
stack.append((i,d+1))
return sum
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